Module 16 · Lesson 16.2
Ductility, and what it buys
Strength reduction factors, the equal-displacement and equal-energy rules, equivalent damping, and the demand that peak displacement does not describe.
Why this matters
The previous lesson showed what a yielding structure does. This one is about the trade an engineer is actually making when they decide to let it yield.
Designing a building to remain elastic in a severe earthquake is possible and almost always uneconomic. The alternative is to design it for a fraction of the elastic force and to detail it so it can survive the displacement that follows. The fraction is the behaviour factor, and choosing it is a decision about how much ductility is genuinely available.
This is where analysis meets design intent, and where a number chosen from a table can quietly commit a structure to a demand it cannot meet.
By the end of this lesson you should be able to
- Apply the equal-displacement and equal-energy rules and know their period ranges
- Convert between required strength, ductility demand and displacement demand
- Explain equivalent viscous damping and why it over-estimates dissipation
- Treat residual displacement as a separate demand from peak displacement
What you should already know
- Hysteresis and the bilinear model (Lesson 16.1)
- Response spectra (Module 14)
- Energy dissipation per cycle (Module 7)
The two rules
Both relate the strength a yielding structure needs to the force an elastic one would attract. Both are observations from computed responses rather than derivations, and both are approximations that have survived because they are useful.
Equal displacement, R = μ. For structures of moderate to long period, the inelastic peak displacement is about the same as the elastic one would have been. If the displacements match, the strength can be reduced in direct proportion to the ductility available. A structure with μ = 4 needs a quarter of the elastic strength.
Equal energy, R = √(2μ − 1). For short-period structures, the areas under the elastic and inelastic force–displacement curves match instead. The reduction is smaller: μ = 4 buys R = 2.65, not 4.
The crossover is around the corner period of the spectrum — roughly 0.5 s, though it depends on the site. Below it, use equal energy. Above it, equal displacement. Very short-period structures get almost no benefit at all: as T → 0 the structure moves with the ground and ductility cannot help it.
The two rules disagree by a factor of about 1.5 at μ = 4. On a stiff building that is the difference between a design that works and one that does not.
What the displacement demand actually is
Under the equal-displacement rule the inelastic peak displacement equals the elastic one. That is easy to state and easy to misread.
It does NOT mean the yielding structure moves the same as the structure you designed. It means it moves the same as the ELASTIC structure of the same initial period would have — the one you did not build and would not have paid for. Since the real structure yields at uy = fy/k, and fy has been reduced by R, the ductility demand is R, and the displacement is R times the yield displacement.
So halving the strength does not halve anything the occupant experiences. It doubles the ductility demand and leaves the displacement where it was.
Equivalent viscous damping, and why it flatters
Hysteretic dissipation is sometimes re-expressed as an equivalent viscous damping ratio, so that a linear analysis can be used with a higher ζ. Equating the energy dissipated per cycle gives, for an elastic–perfectly plastic system,
ζeq = (2/π)(1 − 1/μ)
At μ = 2 that is 31.8%, and at μ = 4 it is 47.7%. Those numbers should provoke suspicion, and they should: they are known to be too large, typically by a third or more.
The reason is in the derivation's assumption. The energy equivalence is set up for STEADY harmonic motion at the peak amplitude — many full loops, all of them at μ. A real earthquake response reaches its peak once or twice and spends the rest of the record on much smaller loops that dissipate far less. Design procedures that use equivalent damping therefore apply an empirical reduction, and the reduction is not a fudge — it is a correction for the difference between a harmonic test and an earthquake.
Residual displacement
When the shaking stops, a structure that yielded does not return to plumb. It stops at a residual displacement, and this is a demand that peak displacement does not describe.
It matters for a practical reason: a building with a large permanent lean may be structurally sound and still be uneconomic to repair. Residual drift has become the governing criterion for demolition decisions after real earthquakes, and it is the reason self-centring systems — rocking walls, post-tensioned frames — exist at all.
Residuals are also badly conditioned. A small change in the record, or in the post-yield stiffness, can change the residual by a large factor while barely moving the peak. A single-record residual is not a reliable number; a mean over a record set is.
Post-yield stiffness is the strongest lever on residual displacement. A system with α = 0 has no restoring tendency once yielded and can stop anywhere; a positive α pulls it back.
When a nonlinear analysis is actually needed
It is expensive, it needs decisions a linear analysis does not, and it can be wrong in ways that look plausible. It is worth it when:
- the structure is expected to yield significantly and the ductility demand needs to be quantified rather than assumed;
- yielding is concentrated, so a global R factor cannot represent it — a soft storey, a knee brace, an isolation system;
- residual displacement or damage sequence is part of the question;
- the structure is being assessed rather than designed, and its real capacity is what is at stake.
It is NOT worth it when the structure is intended to remain essentially elastic, when the question is a serviceability one, or when the model's material properties are not known well enough to justify the precision the method implies. A nonlinear analysis of a structure whose yield strength is known to ±25% reports its results to three figures and means none of them.
Worked example
Choosing a behaviour factor and living with the consequence
Given
- A steel moment frame, elastic period T₁ = 0.90 s
- Elastic spectral acceleration at that period: 0.62 g
- Seismic mass 240 tonnes
- Detailing gives a reliable ductility capacity of μ = 4
Find
The design base shear, the ductility demand it implies, and the displacement to be accommodated.
Assumptions
- Single mode dominant; equal-displacement rule applies at 0.90 s
- Ductility capacity is a member-level capacity that has been checked
Predict first
Two identical frames are designed for the same site, one with R = 1 (elastic) and one with R = 4. Both have the same initial stiffness and period of 1.2 s. How do their peak displacements compare?
Practice
A structure has an elastic base shear demand of 1 460 kN and is designed with a behaviour factor of 4. What is the design base shear, in kN?
Practice
An elastic–perfectly plastic system reaches a ductility of 4. What equivalent viscous damping ratio does the energy-equivalence formula ζeq = (2/π)(1 − 1/μ) give, as a percentage?
Practice
The same formula at a ductility of 2 gives what equivalent damping ratio, as a percentage?
Practice
A frame yields at 31.2 mm and is expected to reach a ductility of 4. What peak displacement should the cladding connections be detailed for, in millimetres?
Check yourself
Which rule should be used to relate strength reduction and ductility for a stiff, short-period structure?
Check yourself
Two nonlinear analyses of the same building under different records give peak displacements within 5% of each other but residual displacements differing by a factor of three. What should be concluded?
Worked example
What a ductility of four is worth
Given
- A structure designed to reach a displacement ductility of 4
- Two candidate rules: equal displacement and equal energy
Find
The strength reduction each rule permits
Worked example
Reading a secant period off a hysteresis loop
Given
- A structure with an elastic period of 0.6 s
- It is pushed to a ductility of 4, behaving elastic–perfectly plastic
Find
The effective period at peak displacement
Summary
- R = μ above the corner period; R = √(2μ − 1) below it, and the two differ by about 1.5 at μ = 4
- A behaviour factor reduces strength, not displacement — drift must be amplified before it is checked
- Equivalent viscous damping from energy equivalence over-states dissipation, typically by a third
- Residual displacement is a separate demand, badly conditioned, and needs a record set
- Post-yield stiffness is the strongest lever on residual displacement
- Nonlinear analysis earns its cost when ductility demand, concentration or residuals are the question
This is educational material. It uses simplified examples to teach principles, and must not be relied on for real design or safety-critical decisions. Module overview and checkpoint