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Module 15 · Lesson 15.2

Comparing layouts before sizing

Maxwell's load path: a structural volume computed from an analysis you have already run, and an invariant that makes the comparison fair.

Why this matters

At concept stage you want to compare four bracing arrangements, or six truss forms, before choosing sections for any of them. Comparing them by weight requires designing them all, which is the work you are trying to avoid.

There is a measure that needs no sections at all, computes from the analysis you have already run, and carries a genuine invariant that makes the comparison fair rather than merely convenient.

By the end of this lesson you should be able to

  • Compute a structural volume from member forces and lengths
  • State the invariant and say what conditions it requires
  • Explain why the comparison must use the same loads and support positions
  • List what the measure omits, and when each omission changes the ranking

The measure

For a structure working in axial load, the area a member needs is roughly proportional to the force it carries. Its volume is area times length, so it is proportional to force times length. Sum that over the structure:

Structural volume = Σ |F|·L

A layout with a smaller sum needs less material. No section sizes are involved, so it can be computed the moment an analysis runs — and it can compare layouts that would need completely different sections.

The invariant

The measure would be merely convenient if that were all. What makes it a theorem is this: split the sum into tension and compression parts, and take the difference:

Σ F·L over tension members − Σ |F|·L over compression members = constant

For a given set of loads at given positions and supports at given positions, that difference does not change however you rearrange the structure between them. It equals the work the external forces — applied loads and reactions — do on their own positions.

So two layouts with different structural volumes must have the same difference. A tool that shows both makes the theorem checkable rather than quotable, and if the difference is not constant across your comparison, the comparison is not fair — something about the loads or the supports has changed.

Making the comparison fair

The invariant needs the same loads at the same points and the same reactions at the same points. That second requirement is easy to miss.

If the supports are statically indeterminate, the reactions themselves depend on the layout — so the external work changes and the constant stops being one. The fix is to use statically determinate supports in the comparison: a pin and a roller. Then the reactions follow from statics and are identical for every layout.

This course's bracing comparison does exactly that, and the constant comes out at zero — because for a horizontal load applied at a point with determinate supports on a level line, every external force has zero work on its own position. That in turn means the tension and compression load paths must be exactly equal in every layout, which is a strong and checkable claim.

What it omits

Every one of these has reversed a ranking somewhere:

  • Buckling. A compression member must also be stable, so its real volume exceeds the load path. Compare like with like — or design the members.
  • Connections. Not in the number at all. In timber, connections routinely drive member size, and the ranking can invert.
  • Fabrication, transport and erection. Absent.
  • Repetition. A layout with twenty distinct members scores the same as one with three, all else equal.

The library returns these caveats alongside every result, so an interface cannot display the number without them. That is deliberate: a measure this convenient gets over-trusted, and the omissions are where the over-trust bites.

Maxwell's load path

What it calculates: A comparable measure of material demand, before any section is chosen

Fi
Axial force in member i (kN)
Li
Length of member i (m)
V
Structural volume — the quantity to minimise (kN·m)

This assumes

  • Members carry axial load only, and area is proportional to force
  • The same loads at the same positions and the same reactions at the same positions
  • Compression members are not governed by buckling — otherwise their real volume is larger

In plain terms: The invariant is what makes this a theorem rather than a convenience. It says the sum is not arbitrary: a layout that reduces the tension load path must reduce the compression one by exactly as much, so you can optimise against either alone and get the same ranking.

Try it

Ground structure explorer

Start with every member and remove the ones carrying least. The tool backs off when a removal would create a mechanism.

Remove members carrying less than this fraction of the largest force.

Members at the start
23
Members kept
23
Members removed
0
Structural volume at the start
10587 kN·m
Structural volume now
10587 kN·m
Still standing?
yes
Iterations
1

Nothing was removed at this threshold: every member is carrying more than the cut-off. Raise it and watch the lightly-loaded members go.

The same idea, applied to four bracing layouts

Same load, same support positions, statically determinate — so the comparison is fair.
LayoutVolume (kN·m)Topology constant
K-bracing14330.000
Knee brace (asymmetric)16000.000
Single diagonal17330.000
X-bracing17330.000

The topology constant is identical for all four — zero, here, because every external force has zero work on its own position. That is the check that the comparison is fair. If it drifted, something about the loads or the supports would have changed and the volumes would not be comparable.

What the load path does not include

  • A compression member also has to be stable, so its real volume is larger than the load path suggests. Compare like with like, or design the members.
  • Connections are not in this number. Where connections drive member size — timber especially — the ranking can reverse.
  • It assumes member area is proportional to force, which is true for ties and only approximately true for struts.
  • The lightest structure is not automatically the cheapest, the lowest-carbon, the simplest or the most robust.

What this shows: Layout optimisation is a search, not a formula — the answer depends on where you started and on the removal rule you chose.

Worked example

Four ways to brace one bay

Given

  • A single bay, 6 m wide and 4 m high
  • A horizontal load of 100 kN applied at the top left corner
  • Supports: pinned at bottom left, roller at bottom right — statically determinate
  • Four arrangements: X-bracing, single diagonal, K-bracing, and a knee brace

Find

Which arrangement demands least material, and whether the comparison is fair

    Practice

    A three-member truss carries forces of +240 kN over 5 m, −180 kN over 4 m and +90 kN over 6 m. Compute its structural volume in kN·m.

    Practice

    For the same truss, compute the topology constant: tension load path minus compression load path, in kN·m.

    Check yourself

    Why does comparing layouts before sizing them save effort?

    Summary

    • Structural volume is Σ|F|·L and needs no sections
    • Tension minus compression load path is invariant for fixed loads and reactions
    • Determinate supports make the comparison fair; indeterminate ones do not
    • Check the invariant before trusting the ranking
    • Buckling, connections, fabrication and repetition are all outside the measure
    Progress is kept in this browser only.

    This is educational material. It uses simplified examples to teach principles, and must not be relied on for real design or safety-critical decisions. Module overview and checkpoint